STRING.trimLeft

Removes leading blank space (ASCII 32) characters.

Syntax

trimLeft( )
       RETURNS STRING

Usage

The trimLeft() method removes the leading blank space characters of the current STRING variable and returns a new string.

Note: The method removes only blank space (ASCII(32)) characters. Characters tab (\t), newline (\n), carriage-return (\r) and form-feed (\f) are not removed.

If the original STRING variable is NULL, the result will be NULL.

Example

MAIN
  DEFINE s STRING
  LET s = "     Some text"
  DISPLAY "["||s.trimLeft()||"]"
END MAIN

Output:

[Some text]